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2014云南高考 第一篇_2014云南高考理综试题及答案

2014年普通高等学校招生考试

新课标II理综试题

14.甲乙两汽车在一平直公路上同向行驶。在t=0到t=t1的时间内，它们的v-t图像如图所示。在这段时间内

A.汽车甲的平均速度比乙大 B.汽车乙的平均速度等于

v1v2

2

C.甲乙两汽车的位移相同 D.汽车甲的加速度大小逐渐减小，汽车乙的加速度大小逐渐增大

15.取水平地面为重力势能零点。一物块从某一高度水平抛出，在抛出点其动能与重力势能恰好相等。不计空气阻力，该物块落地时的速度方向与水平方向的夹角为（ ）

A.

16.一物体静止在粗糙水平地面上，现用一大小为F1的水平拉力拉动物体，经过一段时间后其速度变为v，若将水平拉力的大小改为F2， 物体从静止开始经过同样的时间后速度变为2v，对于上述两个过程，用WF1、WF2分别表示拉力F1、F2所做的功，Wf1、Wf2分别表示前后两次克服摩擦力所做的功，则（ ）

A. WF2＞4WF1，Wf2＞2Wf1 B. WF2＞4WF1，Wf22Wf1 C. WF2＜4WF1，Wf22Wf1 D. WF2＜4WF1，Wf2＜2Wf1

17.如图，一质量为M的光滑大圆环，用一细轻杆固定在竖直平面内；套在大圆环上的质量为m的小环

5

B. C. D. 64312

（可视为质点），从大圆环的最高处由静止滑下，重力加速度为g。当小圆环滑到大圆环的最低点时，大圆环对轻杆拉力的大小为：

A. Mg-5mg B. Mg+mg C. Mg+5mg D. Mg+10mg

18.假设地球可视为质量均匀分布的球体，已知地球表面的重力加速度在两极的大小为g0，在赤道的大小为g；地球自转的周期为T，引力常数为G，则地球的密度为：

A.

19.关于静电场的电场强度和电势，下列说法正确的是：

A.电场强度的方向处处与等势面垂直 B.电场强度为零的地方，电势也为零 C.随着电场强度的大小逐渐减小，电势也逐渐降低 D.任一点的电场强度总是指向该点电势降落最快的方向

20.图为某磁谱仪部分构件的示意图。图中， 永磁铁提供匀强磁场，硅微条径迹探测器可以探测粒子在其中运动的轨迹。宇宙射线中有大量的电子、正电子和质子。当这些粒子从上部垂直进入磁场时，下列说法正确的是：

A.电子与正电子的偏转方向一定不同 B.电子和正电子在磁场中的运动轨迹一定相同

C.仅依据粒子的运动轨迹无法判断此粒子是质子还是正电子 D.粒子的动能越大，它在磁场中运动轨迹的半径越小

g3g-g333g0

B. C. D. =

2222g0GTGTg0-gGTGTg

21.如图，一理想变压器原、副线圈的匝数分别为n1、n2。原线圈通过一理想电流表

接正弦交流电

源，一个二极管和阻值为R的负载电阻串联后接到副线圈的两端；假设该二极管的正向电阻为零，反向电阻为无穷大；用交流电压表测得a、b端和c、d端的电压分别为Uab和Ucd，则：

A.Uab:Ucd=n1:n2 B.增大负载电阻的阻值R，电流表的读数变小

C.负载电阻的阻值越小，cd间的电压Ucd 越大 D.

将二极管短路，电流表的读数加倍

22.在伏安法测电阻的实验中，待测电阻Rx约为200Ω，电压表V的内阻约为2kΩ，电流表A的内阻约为10Ω，测量电路中电流表的连接方式如图（a）学 科 或图（b）所示，计算结果由Rx

=

U计I

算得出，式中U与I分别为电压表和电流表的读数；若将图（a）和图（b）中电路测得的电阻值分别记为Rx1和Rx2，则 ① （填“Rx1”或“Rx2”）更接近待测电阻的真实值，且测量值Rx1 ② （填“大于”、“等于”或“小于”）真实值，测量值Rx2 ③ （填“大于”、“等于”或“小于”）真实值。

23.某实验小组探究弹簧的劲度系数k与其长度（圈数）的关系；实验装置如图（a）所示：一均匀长弹簧竖直悬挂，7个指针P0、P1、P2、P3、P4、P5、P6分别固定在弹簧上距悬点0、10、20、30、40、50、

60圈处；通过旁边竖直放置的刻度尺，可以读出指针的位置，P0指向0刻度；设弹簧下端未挂重物时，各指针的位置记为x0；挂有质量为0.100kg砝码时， 各指针的位置记为x；测量结果及部分计算结果如下表所示（n为弹簧的圈数，取重力加速度为9.80m/s）.已知实验所用弹簧的总圈数为60，整个弹簧的自由长度为

11.88cm.

2

（1）将表中数据补充完整： ① ， ② ；

（2）以n为横坐标，1/k为纵坐标，在图（b）给出的坐标纸上画出1/k-n图像；

（3）图（b）中画出的直线可以近似认为通过原点；若从实验中所用的弹簧截取圈数为n的一段弹簧，该弹簧的劲度系数k与其圈数n的关系的表达式为k= ③ N/m；该弹簧的劲度系数k与其自由长度

l0(单位为m)的表达式为k= ④ N/m

.

24.2012年10月，奥地利极限运动员菲利克斯·鲍姆加特纳乘气球升至约39km的高空后跳下，经过4分20秒到达距地面约1.5km高度处，打开降落伞并成功落地，打破了跳伞运动的多项世界纪录，取重力加速度的大小g10m/s

（1）忽略空气阻力，求该运动员从静止开始下落到1.5km高度处所需要的时间及其在此处速度的大小 （2）实际上物体在空气中运动时会受到空气阻力， 高速运动受阻力大小可近似表示为fkv，其中v为速率，k为阻力系数，其数值与物体的形状，横截面积及空气密度有关，已知该运动员在某段时间内高速下落的vt图象如图所示，着陆过程中，运动员和所携装备的总质量m100kg，试估算该运动员在达到最大速度时所受阻力的阻力系数（结果保留1位有效数字）

2

2

2014云南高考 第二篇_2014云南省高考数学 (理)

一、选择题：本大题共12小题。每小题5分,在每个小题给出的四个选项中，只有一项是符合题目要求的。

（1） 设集合M={0，1，2}，集合N={x|x2-3x+20},则M∩N=

A．{1} B．{2} C．{0，1} D．{1，2}

（2） 设复数z1,z2在复平面内的对应点关于虚轴对称，z1=2+i，则z1z2=

A．-5 B．5 C．-4+i D．-4-i (3 ) 设向量a,b满足|a+b

a-b

则a·b=

A．1 B．2 C．3 D．5 (4) 锐角三角形ABC的面积是

1

则AC= 2

A．5 B

C．2 D．1

(5) 某地区空气资料表明，一天的空气质量为优良的概率是 0.75,连续两天为优良的概率是0.6，已知某天的空气质量为优 良，则随后一天的空气质量为优良的概率是 A．0.8 B．0.75 C．0.6 D．0.45

(6) 如图，网格纸上正方形小格的边长为1（表示1cm），

图中粗线画出的是某零件的三视图，该零件由一个底面 半径为3cm，高为6cm的圆柱体毛坯切削得到，则切削 掉的体积与原来毛坯体积的比值为

175A． B．

279101C． D．

273

(7) 执行右面的程序框图，如果输入的x,t均为2， 则输出的S=

A．4 B．5 C．6 D．7

(8) 设曲线y=ax-ln(x+1)在点（0，0）处的切线方程为y=2x,则a= A．0 B．1 C．2 D．3

xy70

(9) 设x,y满足约束条件x3y10,则z=2x-y的最大值为

3xy50

A．10 B．8 C．3 D．2

(10) 设F为抛物线C：y2=3x的焦点，过F且倾斜角为30°的直线交C于A，B两点，O为坐标原点，则△OAB的面积为 A

．

963 B

． C． D．

43248

（11） 直三棱柱ABC-A1B1C1中，BAC=90°，M，N分别是A1B1，A1C1的中点，BC=CA=CC1,则BM

与AN所成角的余弦值为

A．

41 B． C

． D

．

510102

(12) 设函数

x2

,若存在f(x)的极值点x0满足x0[f(x)]2m2,则m的取值范围是 m

A．（-∞,-6）∪ (6,+ ∞) B．（-∞,-4）∪ (4,+ ∞) C．（-∞,-2）∪ (2,+ ∞) D．（-∞,-2）∪ (2,+ ∞)

第Ⅱ卷

二、填空题：本大题共4小题，每小题5分。

(13) (x+a)10的展开式中，x7的系数为15,则a= (用数字作答) (14) 函数f(x)=sin(x+2φ)-2sinφcos(x+φ)的最大值为

(15) 已知偶函数f(x)在[0,)上单调递减，f(2)=0,若f(x-1)>0,则x的取值范围是 (16) 设点M（x0,1）,若圆O：x2+y2=1上存在点N，使得∠OMN=45°,则x0的取值范围是

三．解答题：解答应写出文字说明，证明过程或演算步骤。 (17) （本小题满分12分）

已知数列{an}满足a1=1,an+1=3an+1. (I) 证明{ an + (II) 证明

(18) （本小题满分12分）

如图，四棱锥P-ABCD中，底面ABCD为矩形，PA⊥平面ABCD，E为PD的中点。 (I) 证明：PB∥平面AEC

。

(II) 设二面角D-AE-C为60°求三棱锥E-ACD的体积。

1

}是等比数列，并求{an}的通项公式。 2【2014云南高考】

111a1a2a3



13 an2

（19） （本小题满分12分）

某地区2007年至2013年农村居民家庭人均纯y（单位：千克）的数据如下表：

(I) 求y关于t的线性回归方程。

(II) 利用(I)中的回方程，分析2007年至2013年该地区农村居民家庭人均纯收入的变化情况，并预测该地区2015年农村居民家庭人均纯收入。

附：回归直线的低斜率和截距的最小二乘法估计公式分别为：

b

(t

i1

n

i

t)(yiy)

,aybt

2t)i

(t

i1

n

（20）（本小题满分12分）

x2y2

设F1，F2分别是椭圆C：221(ab0)的左，右焦点，M是C上一点且MF2与x轴垂

ab

直，直线MF1与C的另一个焦点交为N。 (I) 若直线MN的斜率为

3

，求C的离心率。 4

(II) 若直线MN在y轴上的截距为2，且|MN|=5|F1N|,求a,b.

(21) （本小题满分12分）

已知函数f(x)=ee

x

x

2x

(I) 讨论f(x)的单调性。

(II) 设g(x)=f(2x)-4bf(x).当x>0时，g(x)>0,求b的最大值。 (III) 已知估计ln2的近似值。（精确到0.001）

(22) （本小题满分10分）

如图，P是⊙O处一点，PA是切线，A为切点，割线PBC 与⊙O相交于点B，C， PC=2PA，D为PC的中点，AD 的延长线交⊙O于点E。证明：

(I) BE=EC

(II) ADDE=2PB2

(23) （本小题满分10分）

在直角坐标系xOy中，以坐标原点为极点，x轴正关轴为极轴建立极坐标系，半圆C的极坐标方

程为2cos,[0,



2

]

(I) 求曲线C的参数方程。

(II) 设点D在C上，C在D处的切线与直线

l:y2垂直，根据（1）中你得到的参数方程，确定D点的坐标。

(24) （本小题满分10分）

设函数f(x)=|x+

1

|+|x-a| (a>0) a

(I) 证明f(x)≥2 .

(II) 若f(3)<5,求a的取值范围。 参考答案附后

2014云南省高考数学 新课标2 （理）答案

一、选择题 1. 解析D

0,经检验x=1,2满足。所以选D. 把M=｛0,1,2}中的数,代入不等式x2-3x+2≤

2. 解析A

z12i,z1与z2关于虚轴对称，z2-2i,z1z2-1-4-5,故选A.

2

2

3. 解析A

|+|=,|-|=,，∴++2=10+-2=6,联立方程解得ab=1,故选A.

22

4. 解析B

1112

acsinB=•2•1•sinB=∴sinB=,2222π3ππ

.当B=时，经计算ΔABC为等腰直角三角形，不符合题意，舍去。 ∴B=,或

4443π

∴B=，使用余弦定理，b2=a2+c2-2accosB,解得b=.故选B.

4SΔABC=

5. 解析 A

设某天空气质量优良，则随后一个空气质量也优良的概率为p,则据题有0.6=0.75•p,解得p=0.8,故选A.【2014云南高考】

6. 解析 C

加工前的零件半径为3，高6，∴体积v1=9π•6=54π.

加工后的零件，左半部为小圆柱，半径2，高4，右半部为大圆柱，半径为3，高为2.

∴体积v=4π•4+9π•2=34π.2

∴削掉部分的体积与原体积之比=

7. 解析 D

54π-34π10

=.故选C.54π27

x2,t2,变量变化情况如下： M S K

1 3 1 2 5 2 2 7 3 故选D.

8. 解析 D

2014云南高考 第三篇_2014云南高考英语真题

2014年普通高等学校招生全国统一考试新课标2卷

英 语

本试卷分第I卷（选择题）和第II卷（非选择题）两部分。考试结束后，将本试卷和答案卡一并交回。 注意事项：

1．答第I卷前考生务必将自己的姓名、准考证号填写在答题卡上。

2．选出每小题答案前，用2B铅笔把答题卡上对应题目的答案标号涂黑。如需改动,用橡皮擦干净后,再选涂其他答案标号框,不能答在本试卷上，否则无效。

第一部分 阅读理解（共两节，满分40分）

第一节 (共15小题；每小题2分，满分40分)

阅读下列列短文，从学科网每题所给的四个选项(A、B、C和D)中,选出最佳选项。并在答题卡上将该选项涂黑．

A

Arriving in Sydney on his own from India, my husband ,Rashid, zxxkstayed in a hotel for a short time while looking for a short time while looking for a house for me and our children.

During the first week of his stay, he went out one day to do some shopping. He came back in the late afternoon to discover that his suitcase was gone. He was extremely worried as the suitcase had all his important papers, including his passport.

He reported the case to the police and then sat there，lost and lonely in strange city, thinking of the terrible troubles of getting all the paperwork organized again from a distant country while trying to settle down in a new one.

Late in the evening, the phone rang. It was a stranger. He was trying to pronounce my husband’s name and was asking him a lot of questions. Then he said they had found a pile of papers in their trash can（垃圾桶）that had been left out on the footpath.

My husband rushed to their home to find a kind family holding all his papers and documents. Their young daughter had gone to the trash can and found a pile of unfamiliar papers. Her parents had carefully sorted them out, although they had found mainly foreign addresses on most of the documents. At last they had seen a half-written letter in the pile in which my husband had given his new telephone number to a friend.

That family not only restored the important documents to us that day but also restored our faith and trust in people.We still remember their kindness and often send a warm wish their way.

1.What did Rashid plan to do after his arrival in Sydney?

A.Go shopping

B.Find a house

C.Join his family

D.Take his family

2.The girl’s parents got Rashid’s phone number from_______.

A.a friend of his family

B.a Sydney policeman

C.a letter in his papes

D.a stranger in Sydney

3.What does the underlined word“restored”in the last paragraph mean?

A.Showed

B.Sent out

C.Delivered

D.Gave back

4.Which of the following can be the best title for the text?

A.From India to Australia.

B.Living in a a New Country.

C.Turning Trash to Treasure.

D.In Search of New Friends.

B

Since the first Earth Day in 1970,American have gotten a lot “greenter” toward the environment . “We didn’t know at that time there even was an environment,let alone that there was a problem with it,”says Bruce Anderson,president of Earth Day USA.

But what began as nothing important in public affairs has grown into a social movement .Business people,political leaders,university professors,and especially millions of grass-roots Americans are taking part in the movement. “The understanding has increased many ,many times,”says Gaylord Nelson,the fromer

govermor from Wisconsin,who thought up the firstAccording to US government reports , emissions (排放)from cars and trucks have dropped from 10.3 million tons a year to 5.5 tons .The number of cities producing CO beyond the standard has been reduced from 40 to 9 .Although serious problems still remain and need to be dealt with , the world is a safer and healthier place .A kind of “Green thinking ” has become part of practices .

Great improvement has been achieved .In 1988 there were only 600 recycling programs ,; today in 1995 there are about 6,600 .Advanced lights ,motors , and building designs have helped save a lot of energy and therefore prevented pollution .

Twenty –five years ago , there were hardly any education programs for environment .Today , it’s hard to find a public school , university , or law school that does not have such a kind of program .” Until we do that , nothing else will change! ” say Bruce Anderson .

5 According to Anderson , before 1970, Americans had little idea about ___

A the social movement

B recycling techniques

C environmental problems

D the importance of \Earth Day

6 Where does the support for environmental protection mainly come from?

A The grass –roots level

B The business circle

C Government officials

D University professors

7 What have \Americans achieved in environmental protection ?

A They have cut car emissions to the lowest

B They have settled their environmental problems

C They have lowered their CO levels in forty cities.

D They have reduced pollution through effective measures .

8.What is especially important for environmental protection according to the last pargraph ?

A Education

B Planning

C Green living

D CO reduction

C

One of the latest trend（趋势） in American Childcare is Chinese au pairs. Au Pair in Stamford, for example, has got increasing numbers of request for Chinese au pairs zxxkfrom aero to around 4,000 since 2004. And that’s true all across the country.

“I thought it would be useful for him to learn Chinese at an early age” Joseph Stocke, the managing director of s company, says of his 2-year old son. “I would at least like to give him the chance to use the language in the future,” After only six months of being cared by 25-year-old woman from China, the boy can already understand basic Chinese daily expressions, his dad says.

Li Drake, a Chinese native raising two children in Minnesota with an American husband, had another reason for looking for an au pair from China. She didn’t want her children to miss out on their roots.” Because I am Chinese, my husband and I wanted the children to keep exposed to(接触) the language and culture.” she says.

“Staying with a native speaker is better for children than simply sitting in a classroom,” says Suzanne Flynn, a professor in language education of Children.”But parents must understand that just one year with au pair is unlikely to produce wonders. Complete mastery demands continued learning until the age of 10 or

12.”

The popularity if au pairs from china has been strengthened by the increasing numbers of American parents who want their children who want their children to learn Chinese. It is expected that American demand for au

pairs will continue to rise in the next few years.

9.What does that term” au pair” in the text mean?

A. A mother raising her children on her own

B. A child learning a foreign language at home

C. A professor in language education of children

D. A young foreign woman taking care of children.

10. Li Drake has her children study Chinese because she wants them ______.

A. to live in China some day

B. to speak the language at home

C. to catch up wit other children

D. to learn about the Chinese culturezxxk

11. What can we infer from the text?

A. Learning Chinese is becoming popular In America,

B. Educated woman do better in looking after children

C. Chinese au pairs need to improve their English Skills.

D. Children can learn a foreign language well in six months.

can work well with your appetite and schedule. The more you learn and the more you try, the more ability you have to take control of your food and your schedule.

Hopefully that gives you a good start. 20_______ And don’t let a busy schedule discourage you from making some great changes in the way you eat and live!

A. Try new things.

B. Ability is easily improved.

C. Make three or four instead.

D. Understand your food better.

E. Cooking is a burden for many people.

F. Let cooking and living simply be a joy rather than a burden.

G. A little time planning ahead can save a lot of work later on.

第二部分 英语知识运用（共两节，满分45分）

第一节 完形填空（共20小题；每题1.5分，满分30分）

阅读下面短文，从短文后各题所给的四个选项（A, B, C和D）中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。

Joe Simpson and Simon Yates were the first people zxxkto climb the West Face of the Siula Grande in the Andes mountains. They reached the top 21_______, but on their way back conditions were very 22_______. Joe fell and broke his leg. They both knew that if Simon 23_______ alone, he would probably get back 24_______. But Simon decided to risk his 25_______ and try to lower Joe down the mountain on a rope（绳）.

As they 26_______ down, the weather got worse. Then another 27_______ occurred. They couldn’t see or hear each other and, 28_______, Simon lowered his friend over the edge of a precipice（峭壁）. It was 29_______ for Joe to climb back or for Simon to pull him up. Joe’s 30_______ was pulling Simon slowly towards the precipice. 31_______, after more than an hour in the dark and the icy cold, Simon had to 32_______. In tears, he cut the rope. Joe 33_______ into a large crevasse（裂缝）in the ice below. He had no food or water and he was in terrible pain. He couldn’t walk, but he 34_______ to get out of the crevasse and started to 35_______ towards their camp, nearly ten kilometers 36_______.

Simon had 37_______ the camp at the foot of the mountain. He thought that Joe must be 38_______, but he didn’t want to leave 39_______. Three days later, in the middle of the night, he heard Joe’s voice. He couldn’t 40_______ it. Joe was there, a few meters from their tent, still alive.

2014云南高考 第四篇_2014年云南省高考分数段汇总

历年云南高考录取分数线汇总（2005年至2014年）

2013

云南高考已经落下帷幕，考后考生最关心的就是2013高考分数线划定，为帮助考

生填报志愿，特为各考生整理云南2005-2013年高考录取分数线汇总，供广大考生及家长

参考。

2014云南高考 第五篇_2012年——2014年云南高考数学试题及答案

2012年全国普通高等学校招生理科数学卷（新课标卷Ⅱ）

第I卷

一、 选择题：本大题共12小题，每小题5分，在每小题给同的四个选项中，只有一项是符合题

目要求的。

1、已知集合A{1,2,3,4,5}，B{(x,y)|xA,yA,xyA}，则B中所含元素的个数为（ ）

(A)3 (B)6 (C) (D)

2、将2名教师，4名学生分成2个小组，分别安排到甲、乙两地参加社会实践活动，每个小组由1名教

师和2名学生组成，不同的安排方案共有（ ）

(A)12种 (B)10种 (C)种

(D)种

3、下面是关于复数z

2

的四个命题：其中的真命题为（ ） 1i

p1:z2； p2:z22i；

p3:z的共轭复数为1i； p4:z的虚部为1

(A)p2,p3 (B) p1,p2 (C)p,p

(D)p,p

x2y2

4、设F1，F2是椭圆E：221(ab0)的左、右焦点，

ab3a

P为直线x上一点，F2PF1是底角为30的等腰

2

三角形，则E的离心率为（）

12

(A) (B)

23(C) (D)



5、已知{an}为等比数列，则a1a10 a5a68，a4a72，

(A)7 (B) 5 (C) (D)

1

6、如果执行右边的程序框图，输入正整数N(N2)和实数a1,a2,﹍,an，输出A，B，则（ ）

(A)AB为a1,a2,...,an的和

(B)

AB

2

为a1,a2,...,an的算术平均数 (C)A和B分别是a1,a2,...,an中最大的数和最小的数 (D)A和B分别是a1,a2,...,an中最小的数和最大的数

解析:选C

7、如图，网格纸上小正方形的边长为1，粗线画出的

是某几何体的三视图，则此几何体的体积为（ ）

(A)6 (B) 9 (C) (D)

8、等轴双曲线C的中心在原点，焦点在x轴上，C与抛物线y216x的准线交于A，B

两点，|AB|43；则C的实轴长为（ ）

(A)

(B

) (C) (D)

9、已知0，函数f(x)sin(x

4

)在(2,)上单调递减。则的取值范围是（ ）

(A)[12,54] (B) [12,3

4

] (C) (0,12] (D)(0,2]

10、 已知函数f(x)

1

ln(x1)x

；则yf(x)的图像大致为（ ）

2

11、已知三棱锥SABC的所有顶点都在球O的求面上，ABC是边长为1的正三角形，

SC为球O的直径，且SC2；则此棱锥的体积为（ ）

(A)

(B

)(C

) (D)【2014云南高考】

1x

e上，点Q在曲线yln(2x)上，则PQ最小值为（ ） 2

12、设点P在曲线y

(A)1l

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